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Jumat, 29 Maret 2013

Metode Biseksi (Program Pascal)

program biseksi; uses crt; label ulang; var x1, x2, x3, y1, y2, y3 : real; i : integer; ab : char; begin ulang: clrscr; writeln (‘Tentukan nilai akar dari persamaan f(x)=x^3+x^2-3x-3=0 dengn Metode biseksi’); write (‘Masukan nilai x1= ‘); readln (x1); y1 := x1*x1*x1+x1*x1-3*x1-3; writeln (‘Nilai f(x1)= ‘, y1:0:4); repeat begin write (‘masukan nilai x2 = ‘); readln (x2); y2 := x2*x2*x2+x2*x2-3*x2-3; write (‘Nilai f(x2) = ‘, y2:0:4); end; if (y1*y2) < 0 then writeln (‘Syarat Nilai ok’) else writeln(‘Nilai x2 Belum Sesuai’); until (y1*y2) <0; i := 2; writeln; writeln(‘ Penyelesaian Persamaan dengan metode Biseksi, Nilai x1= ‘, x1:0:2,’ & x2= ‘,x2:0:2); writeln(‘—————————————————————————’); writeln(‘ n x f(x) error ‘); writeln(‘—————————————————————————’); repeat begin i := i+1; x3 := (x1 + x2) /2; y3 := x3*x3*x3+x3*x3-3*x3-3; if (i mod 10)=0 then readln; if i<10 then writeln(‘ ‘,i,’ :: ‘,x3,’ ::’,y3,’ :: ‘,abs( y3 ),’ ::’) else writeln(i,’ :: ‘,x3,’ :: ‘,y3,’ :: ‘,abs( y3 ),’ ::’); if ( y1*y3 ) <0 then begin x2 := x3; end else begin x1 := x3; end; end; until abs( y3)<1E-07; writeln(‘——————————————————————–’); writeln(‘akar persamaannya = ‘,x3); writeln(‘errornya = ‘,abs( y3 )); writeln(‘——————————————————————–’); write(‘Apakah anda ingin mengulanginya (y/t): ‘); readln(ab); if (ab=’y') or (ab=’Y') then begin goto ulang; end else end.

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